-0.95x-x^2+0.255=0

Solution for -0.95x-x^2+0.255=0 equation:

-0.95x-x^2+0.255=0

We add all the numbers together, and all the variables

-1x^2-0.95x+0.255=0

a = -1; b = -0.95; c = +0.255;
Δ = b2-4ac
Δ = -0.952-4·(-1)·0.255
Δ = 1.9225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.95)-\sqrt{1.9225}}{2*-1}=\frac{0.95-\sqrt{1.9225}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.95)+\sqrt{1.9225}}{2*-1}=\frac{0.95+\sqrt{1.9225}}{-2}
$